Just by inspection, and assuming integers, 2^3 3^2 = = 17 But if you want to go through the algebra, using the fact that 2^2=4 and 3^1=3, we have 2^x 3^y = 17 4*2^x 3*3^y = 5 Now, if you let u=2^x and v=3^y, we have u v = 17 4u 2 x 3 y = 17 2 x 2 – 3 y1 = 5 Share with your friends Share 12 the given set of equations are put in eq(1) and eq(2)' therefore equations becomes multiplying eq(3) by 3 and adding to eq(4) put u =8 in eq(3) therefore thus x = 3 and y =2 is the solution of the given equations hope this helps you cheers!!Systemofequationscalculator x2y=2x5, xy=3 en Related Symbolab blog posts High School Math Solutions – Systems of Equations Calculator, Elimination A system of equations is a collection of two or more equations with the same set of variables In this blog
সম ধ ন কর 2 X 3 Y 17 2 X 2 3 Y 1 5
